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9x^2-107x+289=0
a = 9; b = -107; c = +289;
Δ = b2-4ac
Δ = -1072-4·9·289
Δ = 1045
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-107)-\sqrt{1045}}{2*9}=\frac{107-\sqrt{1045}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-107)+\sqrt{1045}}{2*9}=\frac{107+\sqrt{1045}}{18} $
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